There's more than one way to establish relationships between classes Credit: nicodemos / Getty Images In Java 101: Inheritance in Java, Part 1, you learned how to leverage inheritance for code reuse, by establishing is-a relationships between classes. Composition is a closely related programming technique that is used to establish has-a relationships instead. Whereas inheritance extends the features of one class to another, composition allows us to compose one class from another class. The distinction is subtle at first, but it will make more sense once you see it in code. Composition vs inheritance Has-a versus is-a relationships In composition, a class has a field whose type is that of another class. For example, Vehicle has a String field named make. It could also have an Engine field named engine and a Transmission field named transmission: class Vehicle { private String make; private Engine engine; private Transmission transmission; // ... } class Transmission { // ... } class Engine { // ... } In this example, we would say that a vehicle is composed of a make, an engine, and a transmission because it has a make field, an engine field, and a transmission field. In addition to composing classes from other classes, you can use this technique to compose objects from other objects, by storing object references in another object’s fields. Inheritance breaks encapsulation Inheritance is problematic because it breaks encapsulation. You will recall from Java 101: Classes and objects in Java that encapsulation refers to combining constructors, fields, and methods into a class’s body. In inheritance, a subclass relies on implementation details in its superclass. If the superclass’s implementation details change, the subclass might break. This problem is especially serious when a developer doesn’t have complete control over the superclass, or when the superclass hasn’t been designed and documented with extension in mind. (See Java 101: Inheritance in Java, Part 2 for more about working with superclasses.) How to break a subclass: An example To understand this problem, suppose you’ve purchased a library of Java classes that implement a contact manager. Although you don’t have access to their source code, assume that Listing 1 describes the main CM class. Listing 1. Implementing part of a contact manager public class CM { private final static int MAX_CONTACTS = 1000; private Contact[] contacts; private int size; public CM() { contacts = new Contact[MAX_CONTACTS]; size = 0; // redundant because size is automatically initialized to 0 // adds clarity, however } public void addContact(Contact contact) { if (size == contacts.length) return; // array is full contacts[size++] = contact; } public void addContacts(Contact[] contacts) { for (int i = 0; i < contacts.length; i++) addContact(contacts[i]); } } The CM class stores an array of contacts, with each contact described by a Contact instance. For this discussion, the details of Contact aren’t important; it could be as trival as public class Contact {}. Now suppose you wanted to log each contact in a file. Because a logging capability isn’t provided, you extend CM with Listing 2’s LoggingCM class, which adds logging behavior in overriding addContact() and addContacts() methods. Listing 2. Extending the contact manager with support for logging public class LoggingCM extends CM { // A constructor is not necessary because the Java compiler will add a // no-argument constructor that calls the superclass's no-argument // constructor by default. @Override public void addContact(Contact contact) { Logger.log(contact.toString()); super.addContact(contact); } @Override public void addContacts(Contact[] contacts) { for (int i = 0; i < contacts.length; i++) Logger.log(contacts[i].toString()); super.addContacts(contacts); } } The LoggingCM class relies on a Logger class (see Listing 3) whose void log(String msg) class method logs a string to a file. A Contact object is converted to a string via toString(), which is passed to log(). Listing 3. log() outputs its argument to the standard output stream class Logger { static void log(String msg) { System.out.println(msg); } } Although LoggingCM looks okay, it doesn’t work as you might expect. Suppose you instantiated this class and added a few Contact objects to the object via addContacts(): Listing 4. The problem with inheritance class CMDemo { public static void main(String[] args) { Contact[] contacts = { new Contact(), new Contact(), new Contact() }; LoggingCM lcm = new LoggingCM(); lcm.addContacts(contacts); } } If you run this code, you will discover that log() outputs a total of six messages. The problem is that each of the expected three messages (one per Contact object) is duplicated. What happened? When LoggingCM‘s addContacts() method is called, it first calls Logger.log() for each Contact instance in the contacts array that is passed to addContacts(). This method then calls CM‘s addContacts() method via super.addContacts(contacts);. CM‘s addContacts() method calls LoggingCM‘s overriding addContact() method, one for each Contact instance in its contacts array argument. The addContact() method then executes Logger.log(contact.toString());, to log its contact argument’s string representation, and you end up with three additional logged messages. Method overriding and the fragile base class problem If you didn’t override the addContacts() method, this problem would go away. But in that case the subclass would still be tied to an implementation detail: CM‘s addContacts() method calls addContact(). It isn’t a good idea to rely on an implementation detail when that detail isn’t documented. (Recall that you don’t have access to CM‘s source code.) When a detail isn’t documented, it can change in a new version of the class. Because a base class change can break a subclass, this problem is known as the fragile base class problem. A related cause of fragility (which also has to do with overriding methods) occurs when new methods are added to a superclass in a subsequent release. For example, suppose a new version of the library introduces a public void addContact(Contact contact, boolean unique) method into the CM class. This method adds the contact instance to the contact manager when unique is false. When unique is true, it adds the contact instance only if it wasn’t previously added. Because this method was added after the LoggingCM class was created, LoggingCM doesn’t override the new addContact() method with a call to Logger.log(). As a result, Contact instances passed to the new addContact() method are not logged. Here’s another problem: you introduce a method into the subclass that is not also in the superclass. A new version of the superclass presents a new method that matches the subclass method signature and return type. Your subclass method now overrides the superclass method and probably doesn’t fulfill the superclass method’s contract. Composition (and forwarding) to the rescue Fortunately, you can make all of these problems disappear. Instead of extending the superclass, create a private field in a new class, and have this field reference an instance of the superclass. This workaround entails forming a has-a relationship between the new class and the superclass, so the technique you are using is composition. Additionally, you can make each of the new class’s instance methods call the corresponding superclass method and return the called method’s return value. You do this via the superclass instance that was saved in the private field. This task is known as forwarding, and the new methods are known as forwarding methods. Listing 5 presents an improved LoggingCM class that uses composition and forwarding to forever eliminate the fragile base class problem and the additional problem of unanticipated method overriding. Listing 5. Composition and method forwarding demo public class LoggingCM { private CM cm; public LoggingCM(CM cm) { this.cm = cm; } public void addContact(Contact contact) { Logger.log(contact.toString()); cm.addContact(contact); } public void addContacts(Contact[] contacts) { for (int i = 0; i < contacts.length; i++) Logger.log(contacts[i].toString()); cm.addContacts(contacts); } } Note that in this example the LoggingCM class doesn’t depend upon implementation details of the CM class. You can add new methods to CM without breaking LoggingCM. To use the new LoggingCM class, you must first instantiate CM and pass the resulting object as an argument to LoggingCM‘s constructor. The LoggingCM object wraps the CM object, as follows: LoggingCM lcm = new LoggingCM(new CM()); In conclusion In this Java tip you’ve learned the difference between composition and inheritance, and how to use composition to assemble classes from other classes. You also learned that composition resolves one of the main programming challenges associated with inheritance, which is that it breaks encapsulation. Composition is an important programming technique for situations where future developers are unlikely to have access to or control over the superclass. It’s an especially critical technique for cases where a class package or library has not been designed and documented with extension in mind. What does it mean to design and document for class extension? Design means to provide protected methods that hook into the class’s inner workings (to support writing efficient subclasses) and ensure that constructors and the clone() method never call overridable methods. Document means to clearly describe the impact of overriding methods. You might also be wondering when you should extend a class or use a wrapper. Extend a class when there is an is-a relationship between the superclass and the subclass, and either you have control over the superclass or the superclass has been designed and documented for class extension. Otherwise, use a wrapper class. Finally, you might have heard that you shouldn’t use wrapper classes in a callback framework, an object framework where an object passes its own reference to another object (via this), so that the latter object can call the former’s methods at a later time — a callback. You shouldn’t use wrapper classes in this context because the wrapped object doesn’t know of its wrapper class (it passes only its reference via this) and resulting callbacks don’t invoke the wrapper class’s methods. Related content feature What is Rust? Safe, fast, and easy software development Unlike most programming languages, Rust doesn't make you choose between speed, safety, and ease of use. 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